For Beginners Math

Introduction to beginners math:

Mathematics is the study of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions. There is debate over whether mathematical objects such as numbers and points exist naturally or are human creations. The mathematician Benjamin Peirce called mathematics "the science that draws necessary conclusions". (Source: Wikipedia)

I like to share this Matrix Addition with you all through my article.

Example problems for beginners math:


Beginners math - Addition problem:

There are 20 passengers in train A and 15 passengers in train B. How many passengers is there altogether in the two trains?

Solution:

Passengers in train A = 20

Passengers in train B = 15

Passengers in train A + Passengers in train B

So, 20 + 15 = 35

There are 35 passengers altogether in the two trains.

Beginners math - - Subtraction problem:

A fruit whole seller had 12 cucumbers. He sold 8 cucumbers. How many cucumbers did he have left?

Solution:

The total amount of cucumbers = 12 cucumbers.

Sold strawberries = 8

Remaining strawberries =?

So, 12 – 8 = 4

He had 4 cucumbers left.

Beginners math - - Multiplication problem:

There are 9 Strawberries in each box. How many are there in 5 boxes?

Solution:

So, 9 × 5 = 45

There are 45 Strawberries in 5 boxes.

Beginners math - Division problem:

Clark bought a sack of 64 kg of flour. He has packed the flour equally into the 4 bags. How many kilograms of flour were there in each bag?

Solution:

64 ÷ 4 = 16

There were 16 kg of flour in each bag.

I have recently faced lot of problem while learning Distance Formula Calculator, But thank to online resources of math which helped me to learn myself easily on net.

Practice problems for beginners math:


1. There are 15 passengers in mini bus A and 13 passengers in mini bus B. How many passengers are there altogether in the two mini bus?

[Answer: 28]

2. A fruit whole seller had 19 sapotas. He sold 8 sapotas. How many sapotas did he have left?

[Answer: 11]

3. There are 5 oranges in each box. How many are there in 6 boxes?

[Answer: 30]

4. Jerry bought a sack of 99 kg of flour. He has packed the flour equally into the 3 bags. How many kilograms of flour were there in each bag?

[Answer: 33]

Help With First Grade Math

Introduction to help with first grade math:

In mathematics, help with first grade math is one of the important topics to understanding the basic concepts of number, measurement, algebra, and geometry. First grade math problems are use different types of arithmetic operations that are simple addition, subtraction, multiplication, and conservation. Learn the important topics of time and also it compares the length and various units of the measurements. For solving different types of problems, here we solve the different types of problems for the first grade students in an easy way. Help with first grade math problem is used to learn the basic concepts in mathematics.

I like to share this Subtraction of Fractions with you all through my article.

Help with First grade math problems:


Some example problems for help with first grade math problems are,

1. Shakespeare has 17 pencils. 12 of them are in orange color and the rest of them are red color. How many of the pencils are in red color?

Solution:  17 – 12 = 5

Answer: Red color pencils = 5

2. William ate 8 cookies and peter ate 5 cookies. How many more cookies did peter eat than William?

Solution: 8 - 5 = 3

Answer: 3 more cookies

3. Adam got 6 new shirts on his mother’s birthday. If he already had 8, how many shirts does Adam have a now?

Solution: 6 + 8 = 14

Answer: 14 Shirts

4. Anderson has to share 10 Chocolates with his friends. How many will each of them get?

Solution:

10 / 2 = 5

Answer: 5 Chocolates each

5. Jackie contains 7 cents of Licorice. If his two brothers also have same licorice means, how many of the licorice all of them have (in cents)?

Solution:

Jackie + 2 = 3

3 × 7 = 21 cents

Answer: All of them have 21 cents of licorice.

6. How many sides are on three squares?

Solution:

1 square contains 4 sides

Three square = 3 × 4 = 12 sides

Answer: Three squares contains 12 sides

7. How many sides for five rectangles are having?

Solution:

1 rectangle = 4 sides

Five rectangle = 4 × 5 = 20 sides

Answer: Five rectangles have 20 sides

8. Angelina saw 3 elephants and 2 tigers outside of the street. How many animals did Angelina see?

Solution:

3 elephants and 2 tigers

= 3 + 2 = 5 animals

Answer: Angelina saw 5 animals.

9. Lincoln have 10 pens, half of them are in red color. How many of the pens are in red color?

Solution:

Total pens = 10

Half of pens = 10/ 2 = 5

Answer: Lincoln has 5 red balls

10. How many vertices are on two triangular prisms?

Solution:

1 triangle prism has 6 vertices

Three triangle prisms = 2 × 6 = 12 vertices

Answer: Two triangle prisms have 12 vertices.

Help with First grade math problem for practice:


A. How many vertices are on 5 triangular prisms?

B. Abraham have 14 balls, half of them are in white color. How many of the balls are in white color?

C.  Lee saw 3 tigers and 4 zebra in a zoo. How many animals did lee see?

D. How many sides are on 4 squares?

E. Peter has 2 cents of Licorice. If his four brothers also have same means, how many of the licorice all of them have (in cents)?

A. 30 vertices

B. 7 balls are in white color

C. 7 animals

D. 16 sides

E. 10 cents

All Answers to Area Math

Introduction to all answers to area math:

Area is the measure of surface occupied by an object. The standard unit for measurement of area is meter square (m2).However the areas of smaller dimensions can be expressed in mm2or cm2.The areas of large amount of dimensions can be expressed in acre or hectare. Here we are going to study about how to calculate the answer for area of the shape and its example problems. (Source from Wikipedia)

I like to share this Area Formula for a Rectangle with you all through my article.

Example problems for all answers to area math:


Example: 1

Find the area of the rectangle with base 8 meter and height is 7 meter

Solution:

We know the formula for find the area of the rectangle is base *height

Area = 8 *7

Area = 56 meter square

math answer:

The area of the given rectangle is 56 meter square.

Example: 2

Find the area of triangle with base 12 meter and height is 9 meter

Solution:

We know the formula for area of triangle,

Area =`1/2 `  (base *height)

Here base = 12 meter and height = 9 meter substitute the above formula we get

Area = `1/2 ` (12 * 9)

Area =`1/2` (108)

= `108/2`

= 54 meter square

math answer:

The area of the triangle is 27 meter square

Understanding free online math solver is always challenging for me but thanks to all math help websites to help me out.

Example problem for all answers to area math: 3


A cylinder with radius 15 cm and height 3 cm calculate the surface area of the cylinder.

Solution:

Cylinder radius is (r) = 15 cm

Height of the cylinder (h) = 3cm

Already we know the formula for finding the surface area of the cylinder is

A = 2`pi` r2 + 2 `pi` r h

Here 2 `pi ` r is common so take out

A= 2 `pi` r (r+h)

Substitute the height and radius of the cylinder in the above formula we get

A= 2 * `pi` * 15 (15+3)

Simplify the above expression

Area = 2 * 3.14 *15 (18)

Area = 94.2 *18

Area = 1695.6

math answer:

Area of the given cylinder = 1695.6 cm square

Prime Numbers in Math

Introduction to Math prime numbers:

In mathematics, a prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself. The first twenty-five prime numbers are:

Prime Numbers:- 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

Condition: - If x is the prime number then the next factors of the number x is 1 and X.                                                                                                                                                                                                                               - Source from Wikipedia


Prime numbers in math:


To finding a prime number up to 100 means we can calculate directly but we need to find above hundred means we have follow the shortcut method.

For example:
Check if 131 is a prime number.

Step 1:

Now we have to take Square root for 131 = 11.44
Now rounding the value 11.4 to the nearest big whole number. We can write 11.4 as 12.

Step 2:

Then find the Prime Numbers below 12. The factors up to 12 are 2, 3, 5, 7, 1

Step 3:
The given number 131 is not divisible by 2, 3, 5, 7 and 11

131 is divisible by and the number itself.
So the number 131 is considered as prime number.


Example problems for math prime number:


Problem 1:

Find whether the number 53 is prime number or not?

Solution:

The given number 53 is a prime number. Why means it includes two factors 1 and 53 only. So the number 53 is a prime number.

Problem 2:

Find whether the number 79 is prime number or not?

Solution;

The given number 79 is divisible by one and itself only. So it is called as prime number.

Problem 3:

Find whether the number 39 is prime number or not?

Solution:

The given number 39 has more than two factors. That is 1, 6, 13 and 39. Hence the given number 39 is not a prime number.

Problem 4:

Find whether the number 434 is prime number or not?

Solution;

The given number 434 has more than two factors. That is 1, 2, 7, 31, 217, and 434. Hence the given number 434 is not a prime number.

Problem: - 5

Find whether the number 638 is prime or not?

Solution:

The given number is 638 has divided by two. So the factors for 638 are 1,2, 11, 29,    319 and 638. Hence 638 is not a prime number.

Practice problem for math prime numbers:

Problem 1:

Find whether the number 43 is prime or not?

Solution:

The given number 43 is a prime number.

Problem 2:

Find whether the number 126 is prime or not?

Solution:

The given number 126 is not a prime number.

Answer Math Questions For Me

Introduction to answer math questions for me:

Answering math questions is a simple one. The math terms for whom it is well known can answer the math questions. The math question involves the various topics in which the each topic can be solved through the different manner. The math questions may have the various methods for the solving purpose but the solution of the question may be the same in whatever method the particular problem is made to solve. I like to share this Solve Fractional Equations with you all through my article.


Answer math questions for me:


The answer math questions are done through the well trained persons who have the certificates under the math. The math can be taught under various methods, it is better to solve in the known steps and also preferring the easy steps for solving the questions. The math questions should be read more than one times to have the cute understandings on the particular topics. These math answers would helps you to have the quite understanding on the methods mentioned below.

Understanding Dividing Fractions Calculator is always challenging for me but thanks to all math help websites to help me out.

Examples for math questions for me:


Example 1:

What is -6+ (-2)?

From above: (- )+(-) becomes a negative sign.

-6+ (-2) = -6 - 2

Answer: -6+ (-2) = -8.

Example 2 : What is -5+ (-2)?

+ (-) gives a negative sign.

-5+ (-2) = -5 - 2 = -7.

Answer: -5+ (-2) = -7.

Example 3: What is -6- (+3)?

- (+) becomes a negative sign.

-6- (+3) = -6 - 3=-9

Example 4: solve 1/3 + 2/6 fraction problem:

=   1/3 + 2/6

Having common denominator has 6 then multiply 3 with 2 then we can have 6 has the common denominator. so multiply 2 with 3 then it becomes 6.

=   2/6 + 2/6

=   4/6

Answer :  2/3.

Example 5: Solve 2/4 + 1/4 fraction problem:

= 2/4 + 1/4

Having common denominator has 4 simply add the numerators  = (2 + 1)/4

= 3/4

Answer: 3/4.

Example 6: Solve 12/5 + 5/6

= 12/5 + 5/6

= [(12 X 6) + (5 X 5)]/ 30

= [72 + 25]/30

= 97/30

Answer: 97/30

Example 7: solve 8/7 + 5/4

= [(8X 4) + (5 X 7)]/4 X 7

= [(32) + (35)]/28

= 67/28

Answer: 67/28

Example 8:

Heights in cms of ten people are:

126, 145, 150, 157, 149, 136, 166, 129, 143, 134

Solution:

Mean: sum of all values/total numbers

Mean= 1435/10

=143.5

Answer: 143.5

Example 9:

The highest scores of the five players in twenty twenty are:

198,192,182,190,179.

Solution:

Mean = sum of all values/total numbers.

= 941/5

Answer: 188.2

Example 10:

Heights in cms of thirteen players are:

110,115,120,125,130,135,150,145,150,155.

Solution:

Mean: sum of all values/total numbers

Mean = 1335/10

= 133.5

Answer: 133.307

Example 11:

The highest scores of the ten players one day are:

198,195,192,190,186,194,182,180,179,178.

Solution:

Mean = sum of all values/total numbers.

= 1874/10

Answer: 187.4

Statistics Free Course

Introduction to Statistics Free Course:
Statistics is the science of making effective use of numerical data relating to groups of individuals or experiments. It deals with all aspects of this, including not only the collection, analysis and interpretation of such data, but also the planning of the collection of data, in terms of the design of surveys and experiments.

Let us study statistics course freely.


Statistics Free Course - Basics concepts:


Arithmetic mean:

The arithmetic mean in statistics is the average of data in arithmetic. A set of data which is divide by sum of observations and number of observations in the given data.

                                       Sum of observations

Arithmetic Mean = --------------------------------------

                                        Number of observations

Median:

The median is a set of numbers which the middle number and find the set of numbers in them. Then arrange the number in order to select the middle number.

Mode:

It is a set of numbers which occurs frequently in the set of data and no number can occur more than once.

Standard Deviation:

The standard deviation is an arithmetical figure which can spread and variability the data. It has the root mean square of values in their arithmetic mean. Is this topic Sum of Two Random Variables hard for you? Watch out for my coming posts.


Examples for Statistics Free Course:


The followings are the examples for statistics free course.

1. Find the arithmetic mean of weights for 6 peoples in kilograms are 45, 18, 65, 82, 78, 33, 71, and 60.

Solution:

                      Sum of total number

Mean = -----------------------------------

                          Total number

                 45 + 18 + 65 + 82 + 78 + 33 + 71 + 60

=  -------------------------------------------------------------------------
                                        10

     452

= ----------
      10

= 45.2

2. Find the median of 12, 10, 24, 18, 45, and 30.

Solution:

Arrange the data in ascending order as 10, 12, 18, 24, 30 and 45.

N = 6

Since n is even, median = `1 / 2` [nth/2 item value + (`n / 2` + 1)th item value]

= `1 / 2` [6th item value + (`6/2` + 1)th item value]

= `1 / 2` [3rd item value + 4th item value]

= `1 / 2` [18 + 24]

= `1 / 2` * 42

= 21

3. Find the mode of 90, 35, 80, 72, and 35.

Solution:

35 are repeated twice.

Mode =35

4. Find the Standard deviation for 2, 5, 1, 9 and 8.

Solution:

Step 1:

To calculate the mean and deviation.

X = 2, 5, 1, 9, 8

M = `(2 + 5 + 1 + 9 + 8) / 5`

= `25 / 5`

= 5

Step 2:

To find the sum of (X - M) 2

9 + 0 + 16 + 16 + 9 = 50

Step 3:

Where N = 5, the total number of values.

Find N - 1.

5 - 1 = 4

Step 4:

To locate Standard Deviation by the method.

√50 / √4 = `7.07 / 2`

= 3.53

Algebra ii Math

Introduction to  algebra ii math:

Algebra ii is one of the important categories in mathematics.

Algebra ii contains the following topics

Solving equations and inequalities

Graphs and functions

Polynomials and factoring

Fractional Expressions

Powers and roots

Complex numbers

Quadratic equation

In this article we shall discuss about the some example problems on algebra ii maths. I like to share this Fractional Coefficients with you all through my article.


Problems on solving equations in algebra ii maths:

X+2y=5

2x-y=10

Solution:

Step 1: To make anyone of the variable as common coefficients

From the above problem multiply the equation 2 by 2 we get,

X+2y=5

4x-2y=20

------------

5x=25

Step 2: Divide by 5 on both sides

5x/5 =25/5

X=5

Step 3: Substitute the value of x in first equation

X+2y=5

5+2y=5

Step 4: Subtract 5 on both sides,

5+2y-5=5-5

2y=0

Y=0

Problems on polynomials and factoring in algebra ii maths:

Factor: x^2-5x-150

Solution:

Step 1: The above equation is quadratic equation because it has the highest degree of 2

Multiply the coefficient of x^2 and constant term

1*-150 = -150

Step 2: Find the factor for the product term. Sum of the factor is equal to coefficients of x

-150 = -15*10

-15+10 = -5

Step 3: Now the equation is written as,

x^2-15x+10x-150

Take the common term outside,

x(x-15)+10(x-15)

(x+10) (x-15)

Understanding Inverse Function Definition is always challenging for me but thanks to all math help websites to help me out.

Problems on fractional expressions in algebra ii maths:


(x+5)/(y-10) + (2x+3)/(y-2)

Solution:

Here the denominators are different. To make the common denominator take the LCD of (y-10) and (y-2).       LCD= (y-10)(y-2)

(x+5)/(y-10) + (2x+3)/(y-2)

(x+5)/(y-10) * (y-2)/(y-2) + (2x+3)/(y-2) * (y-10)/(y-10)

(x+5)(y-2)/(y-10)(y-2) +(2x+3)(y-10)/(y-2)(y-10)

((x+5)(y-2)+ (2x+3)(y-10)) /(y-10)(y-2)

(xy-2x+5y-10)+(2xy-20x+3y-30) / (y-10)(y-2)

(3xy-22x+8y-40) / (y-10)(y-2)

Problems on quadratic equation in algebra ii maths:

Solve the quadratic equation by factoring method and find roots?

2x^2+x-10=0

Solution:

Step 1: Multiply the coefficient of x^2 and the constant term,

2*-10 =-20 (product term)

Step 2: Find the factors for the product term

-20 ---- > -5 *4 = -20 (factors -5 and 4)

-5+4 = 1 (1 is equal to the coefficient of x)

Step 3: Split the coefficient of x as factors

2x^2+x-10=0

2x^2-5x+4x-10=0

Step 4: Taking the common term x for the first two term and 2 for the next two terms

x(2x-5) +2(2x-5) =0

(x+2) (2x-5)=0.

Now set (x+2) =0; x=-2;

(2x-5)=0; x=5/2.

The roots are x=-5/2 and -2.

Problem Solving Math

Introduction to problem solving math:

Problem solving is a mental process and is part of the larger problem process that includes problem finding and problem shaping. Considered the most complex of all intellectual functions, problem solving has been defined as higher-order cognitive process that requires the modulation and control of more routine or fundamental skills. Problem solving occurs when an organism or an artificial intelligence system needs to move from a given state to a desired goal state.                                                                                                                                      Source wikipedia

Problem solving math examples:
Solving math problem 1

Method 1

Add the two fractions `15/64` and `14/64`

Solution:

The given two fractions `15/64` and `14/64`

=`15/64` +`14/64`

= `(15+14)/64`

=`19/64`

This can be simplified has

Answer=0.2968

Solving math problem 2

Add the two fractions `44/6` and `26/6`

Solution:

The given two fractions `44/6` and `26/6`

=`44/6` +`26/6`

=`(44+26)/6`

=`70/6`

=17.66

Answer=17.66

Solving math problem 3

Solve 3x = 2x+18

Solution:

Here the addition operations involved in algebraic expression.

From the given problem 3x = 2x+18

Subtract 2x on both sides,

3x-2x=2x+18-2x

x =18

Answer  x=18

Solving math problems: 4

Find the volume of sphere with diameter 16 meter?

Solution:

Volume of sphere = `4/3` *pi*radius 3.

We know that diameter = 16 m. So we know that radius = diameter/2 =`16/2` =8 m

Plug the radius value in to the formula.

Volume of sphere = 4/3 *3.14*83

So, we get

=2143.57 m3

Answer 2143.57 m3

Understanding Surface Area of a Pyramid is always challenging for me but thanks to all math help websites to help me out.

Additional solving math problems:


Solving math problems: 5

Find out sixty five percentage of fifty six.

Solution:

= 65 * 56/100 (56 multiply with 65)

= 3640/100; (divide by 100)

= 36.4%

Answer is 36.4%.

Solving math problems: 6

Find out seventy nine percentage of fifty seven.

Solution:

= 79 * 57/100 (57 multiply with 79)

= 4503/100; (divide by 100)

Answer= 45.03%

Solving math problems: 7

Find the difference of two mixed number 8`1/3` and 9`1/3`

Solution:

The given mixed numbers are 8`1/3` and 9`1/3`

Initially to perform any operations on mixed numbers we must convert it to fraction

8`1/3` in fraction

Multiply 8 and 3 and add with 1

8`1/3` =` (24+1)/3` =`25/3`

9`1/3` in fraction

Multiply 9 and 3 and add with 1

9`1/3` = `(27+1)/3`

=`28/3`

8`1/3` -9`1/3` =`25/3` -`28/3`

=`(25-28)/3`

=-`3/3`

= -1

Answer:  -1

Number Word Math

Introduction to Number Word Math:

The numbers are the basic source of math. The numbers can be written in many several forms such as word form, expanded form, and standard form and also in place value form. The word form can be written for the numerals or numbers in English words. For example: 1 can be written as one, etc in math. The numbers are the symbolic representation or abstract object of math. Let us see about the numbers in word form in this article. I like to share this Complex Number Calculator with you all through my article.


Representation of Numbers in Word Form


The numbers can be classified into 1 to infinity. Those numbers can be written in words such as:

Counting of Word Form from 1 - 10 for Numbers in Math:

1 – The number 1 can be written as one.

2 – The number 2 can be written as two.

3 – The number 3 can be written as three.

4 – The number 4 can be written as four.

5 – The number 5 can be written as five.

6 – The number 6 can be written as six.

7 – The number 7 can be written as seven.

8 – The number 8 can be written as eight.

9 – The number 9 can be written as nine.

10 – The number 10 can be written as ten.

Counting of Word Form from 11 - 20 for Numbers in Math:

11 – The number 11 can be written as eleven.

12 – The number 12 can be written as twelve.

13 – The number 13 can be written as thirteen.

14 – The number 14 can be written as fourteen.

15 – The number 15 can be written as fifteen.

16 – The number 16 can be written as sixteen.

17 – The number 17 can be written as seventeen.

18 – The number 18 can be written as eighteen.

19 – The number 19 can be written as nineteen.

20 – The number 20 can be written as twenty.


Other Word Forms for Numbers in Math


Counting of Word Form from 21 - 30 for Numbers in Math:

21 – The number 21 can be written as twenty-one.

22 – The number 22 can be written as twenty-two.

23 – The number 23 can be written as twenty-three.

24 – The number 24 can be written as twenty-four.

25 – The number 25 can be written as twenty-five.

26 – The number 26 can be written as twenty-six.

27 – The number 27 can be written as twenty-seven.

28 – The number 28 can be written as twenty-eight.

29 – The number 29 can be written as twenty-nine.

30 – The number 30 can be written as thirty.

Understanding the prime numbers from 1 to 100 is always challenging for me but thanks to all math help websites to help me out.

Problems to Practice in Number Word Math


Example 1:

Write the given number in words?

748

Solution:

Let us write the number 748 in words like,

748 = seven hundred and forty-eight.

Example 2:

Write the given number in words?

93572

Solution:

Let us write the number 93, 572 in words like,

93, 572 = ninety-three thousand five hundred and seventy-two.

Example 3:

Write the given number in words?

403507820

Solution:

Let us write the number 403507820 in words like,

403, 507, 820 = four hundred and three millions, five hundred and seven thousands, eight hundred and twenty.

Math Word Method

Introduction of math word:

In mathematics, especially in the area of abstract algebra known as combinatorial group theory, the word problem for a recursively presented group G is the algorithmic problem of deciding whether two words represent the same element. Although it is common to speak of the word problem for the group G strictly speaking it is a presentation of the group that does or does not have solvable word problem.(Source: Wikipedia)

Please express your views of this topic Definition of Scalene Triangle by commenting on blog.

Math word problems methods:


Math word problems method 1

Twelve years ago, Morgan’s mother was four times older than her daughter. After 12years, the Morgan mother will be twice older than daughter. The present age of Morgan is:

Sol: Let Morgan’s age 12 years ago be x years.

Morgan mother’s age 12 years ago = 4x

(4x+12)+12=2(x+12+12)

x=12

Present age of Morgan= (x+12) = 24years

Answer.24 years

Math word problems method 2

On the first exam of the semester, kisans scored a 75. On the last exam of the semester, kisan scored 95% By what percent did kisan's score improve?

Solution

In first test kisan got 75

In last test he got 95.

% increase in test `( 75(x+100))/100` =95

0.75X+75=95

0.75x=95-75

0.75x=20

x=`20/0.75`

=27%

Answer:= 27%

Math word problems method 3

Orton and Victoria agree to meet in Chicago for the weekend. Orton travels 114 miles and Victoria travels 96 miles. If Orton s rate of   speed is 6mph faster than Victoria ’s then at what rate of speed does Orton travel?

Solution

Take Victoria’s speed =x,

Distance = 96 miles

Then Orton’s speed = x+6,

Distance =114 miles

Distance/speed = time, here time is constant.

Now

`114/(x+6) ` =` (96/x)`

Cross multiply on both sides

114(x)=96(x+6)

114x=96x+576

Subtract 96x on both sides

114x-96x=96x-96x+576

18x=576

Divide by 18 on both sides

`(18/18)x` =`576/18`

We get

x=32 mph

Victoria’s speed=32 mph

For Orton speed= 32+6 =38 mph

Math word problems method 4

The diameter of the driving wheel of a car is 190 cm. How many revolutions per min must the wheel make in order to keep a speed of 75 kmph?

Solution

Distance to be covered in 1 min = `(75*1000)/60` m

=1250m

Circumference of the wheel =2 `pi` r

Radius of the driving wheel = diameter of the driving wheel `/2`

=`190/2`

=95

(2 * `22/7` * 0.95)m=5.966m.

So, Number of revolutions per min   =  `1250/5.966`

=210.

Answer = 210 rpm

I have recently faced lot of problem while learning Area of Hexagon, But thank to online resources of math which helped me to learn myself easily on net.

Practice problem for math word method


Find the cost per pound of a coffee mixture made from 7 lb of coffee that costs $8.20 per pound and 11 lb of coffee that costs $6.50 per pound

Answer ;$7.16

Alternative Activity Math

Introduction to alternative activity math:

Activity learning theory is a psychosomatic meta-theory average by extraction within Vygotsky’s educational chronological phychology. organizer be Alexei N.Leont’ev, along with Sergei Rubinshtein required toward recognize person behavior while composite, generally positioned phenomenon with depart further than phychoanalysis with behaviorism. that develop into individual of main psychosomatic advance within the earlier organism extensively utilize during mutually hypothetical with functional psychology, into district such like education. Having problem with Sum of Binomial Random Variables keep reading my upcoming posts, i will try to help you.


alternative activity math:


Alternative activity theory while those appoint with interrelate by their atmosphere, manufacture of apparatus consequences. These apparatus are exteriorized structure of psychological method, with as these psychological procedure are noticeable in apparatus, they develop into further willingly available with transmissible to new group, fetching constructive for public communication.

Please express your views of this topic List of Composite Numbers to 100 by commenting on blog.

Developments in alternative activity math theory:

Activity learning theory is forceful. It know how to be utilize through a diversity of regulation to recognize the method populace proceed.

Scandinavian alternative activity math theory

This most important instruct of consideration request to combine with enlarge thought as of Vygotsky's Psychology as well as Leont'ev's activity theory such like Cognitive knowledge.

Systemic-structural alternative activity math theory

A collection of Russian activity theorists functioning within the scheme - cybernetic institution begin to distribute and production through during person issue along with ergonomics as well as, recently, person processor communication.

Beneath the rubric of structural activity theory, correspond toward a present mixture in activity theory that pass mutually the scheme structural thread of the institution by conclusion with technique as of cognitive psychology.

The expansion of theory contain be specially leaning to the psychoanalysis with plan of the essential fundamentals of individual employment motion: responsibilities, technique. SSAT include urbanized method for together the quantitative explanation of occupation activity.

Applications to design

Activity theory know how to be utilize to give a structure for notify and appraise plan

In a structure resulting as of activity math theory, some charge, know how to be busted behind into events, that are additional subordinate keen on process. In a plan circumstance, by these group know how to give the exclusive by an considerate of steps essential used for a customer to take away a charge.

Answer Math Question Now

Introduction to mathematics:

Mathematics is the study of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics is used throughout the world as an essential tool in many fields, including natural science, engineering, and medicine. (Source: From Wikipedia). Now, we are going to see some of the question and answer in mathematics. I like to share this What are Variables? with you all through my article.


Math questions and answers:

Example question 1:

Solve for the variable x: 2x + 3 = 5

Solution:

2x + 3 = 5

Subtract 3 on both sides of the equation

2x + 3 – 3 = 5 – 3

2x = 2

Now, divide by 2 on both sides of the equation

2x / 2 = 2 / 2

x = 1

So, the answer is x=1.

Example question 2:

Find the value of the expression: xy+2x+3yz when x=1, y=0 and z=2.

Solution:

xy + 2x + 3yz

Now, substitute the value of x, y and z in the expression

xy + 2x + 3yz = 1(0) + 2(1) + 3(0)(2)

= 0 + 2 + 0

= 2

So, the answer is 2.

Understanding Pythagoras Theorem is always challenging for me but thanks to all math help websites to help me out.

Additional questions and answers in maths:


Example question 3:

The perimeter of the floor of a rectangular hall is 26 m. Its length is 8 m. Find its area.

Solution:

To determine the area we should know the length and breadth of a rectangle. So, we should find the breadth from the perimeter.

2 length + 2 breadth = perimeter

2 × 8 + 2b = 26

16 + 2b = 26

i.e. 2b = 26 – 16

2b = 10

b =10 / 2 = 5

Now the area of the rectangle A = l b

= 8 m × 5 m

= 40 sq.m.

So, the answer is 40 square meter.

Example question 3:

In a right triangle the length of the base is20 cm and the height is 25 cm. Find its area.

Solution:

Let b = 20 cm and h = 25 cm

Now, we know the formula,

Area of the right triangle, A = (1 / 2)*b*h

= (1 / 2) × 20 cm × 25 cm

= 250  sq.cm

So, the answer is 250 square cm.

Example question 5:

The mean marks in mathematics for a class is 42. If there are 50 pupils in the class find the total marks scored by them in mathematics.

Solution:

Total marks / number of pupils = mean

Total marks = mean × number of pupils

= 42 × 50

= 2100.

So, the answer is 2100 marks.