Saturday, May 18, 2013

Answer Math Riddle

Introduction to answer math riddle:
In this section we will study about answer math riddle. Riddles are nothing but a puzzle which helps students to understand the mathematical subject in quick and easy manner. Riddles are basically in the form of word problems. Below we will solve word problems or puzzles. Let us solve the answer math riddle.

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Example problems for answer math riddle:


Example problem 1:

Megan has 4 vases of flowers. Some of the vases contain 9 red roses. The other vases contain 8 pink tulips. There are 34 flowers in the vases in total. How many vases of each type of flower does Megan have?

Solution:

Use guess-and-check to solve the problem. Guess pairs of numbers that add up to 4.

Guess 1: 3 vases of red roses and 1 vase of pink tulips

Find the number of vases: 3 + 1 = 4

Find the total number of flowers: (9 × 3) + (8 × 1) = 27 + 8 = 35

The guess is incorrect.

Guess 2: 1 vase of red roses and 3 vases of pink tulips

Find the number of vases: 1 + 3 = 4

Find the total number of flowers: (9 × 1) + (8 × 3) = 9 + 24 = 33

The guess is incorrect.

Guess 3: 2 vases of red roses and 2 vases of pink tulips

Find the number of vases: 2 + 2 = 4

Find the total number of flowers: (9 × 2) + (8 × 2) = 18 + 16 = 34

The guess is correct. Megan has 2 vases of red roses and 2 vases of pink tulips.

Answer: Megan has 2 vases of red roses and 2 vases of pink tulips.

Example problem: 2

How many balls can you put in an empty bag?

Solution:

We can put only one ball because after putting one ball the bag is not empty.

Answer: One ball


Practice problems for answer math riddle:


Practice problem 1:

Jake scored more points than Destiny. Jake did not score more points than Charlie. Who scored the fewest points?

Answer: Destiny scored the fewest points.

Practice problem 2:

The bicycle warehouse has 235 adult bicycles and 575 children's bicycles. About how many bicycles are there in all?

Answer: 810 bicycles

Friday, May 3, 2013

Functions for Math

Introduction to functions for math
The mathematical concept of a function expresses the intuitive idea that one quantity completely determines another quantity (the value, or the output). A function assigns a unique value to each input of a specified type. The argument and the value may be real numbers, but they can also be elements from any given sets: the domain and the codomain of the function (Source: Wikipedia)

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Functions for math


An illustration of a function through the real numbers since equally its domain also the codomain is the function f(x) = 4x.

This gives to all real number the real number that is to say twice as big.

In this example, we be able to inscribe f(6) = 24.

The domain of the function is the set of every acceptable input to a specified function.

The image or else range of the function is the set of every resultant outputs.

The representation is frequently a subset of various larger set, called the codomain of a function. consequently such as, the function f(x) = x2 might obtain since its domain the set of every real numbers as its representation the set of every non-negative real numbers, as well as its codomain the set of every real numbers.

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Examples for functions math


Example 1

If f (2, 7) = 57 and f(1, 6) = 37, what is the value of (4, 10)?

Solution

The function f (a, b) = a^3 + b^2

f (2, 7) t is = 2^3 + 7^2 = 8 + 49 = 57
f (1, 6) = 1^3 + 6^2 = 1 + 36 = 37.

Therefore, f (4, 10) = 4^3 + 10^2 = 64 + 100 = 164.

The value of (4, 10) = 164

Example 2

Suppose the given function f(x) is 6x+7. Finding the value of f (3) and f(7)?

Solution

Given function f(x) = 6x+7

Find the value of f (3)

Substitute the value x for 3, then

f (3) = 6x3+7

=18+7

f (3) = 25

Find the value of f (7)

Substitute the value x for 7, then

f (7) = 6x7+7

=42+7

f (7) = 49

What is a Monomial in Math

Introduction of what is a monomial in math:

Polynomial:

Polynomial is an expression represented by constant numbers and variables.These expression may be contains terms from one to many.

Classification of polynomial:

Monomials
Binomials
Trinomials
In this chapter we will discuss about what is a monomial.

Monomials: In mathematics, an equation has a term alone is considered as a monomial. On the other hand we can say that an algebraic expression having a sole term is considered as monomial in maths.

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what is a monomial in math


What is monomial in math:

A monomial algebraic expression may have a single constant or the constant is join with the variable having powers. For example, the constant 90 alone is monomial. If it is joined with v2, then 90v2 is also monomial.

Operation performed in monomial:

Multiplication
Division
Multiplication:

Step 1: First multiply the constants.
Step 2: Now multiply the variables by adding the powers. This process is valid only for same variables.
Division:

Step 1: The constant are divided separately.
Step 2: The variables are divided by subtracting the powers of variables.

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Example problems for monomial in math:


Example: 1

What is the monomial term in the following choices?

a. 5698

b. 588+o

c. vy+123

d. 34-9

Solution:

The second answer contains a + sigh with two terms, third answer also contains + sign with two terms and the third answer contains fraction part as its power, so these all are not monomial. The first answer contains a single term of constant, so the answer is first choice.

Ans: 5698

Example: 2

What is the answer for the following monomial term?

Multiply: (15x) with (12x)

Solution:

Given, (15x)`xx` (12x)

Step 1: 15 `xx` 12=180

Step 2: x `xx` x=x(1+1)=x ^2

Step 3: The answer is 180x ^2

Example: 3

What is the answer for the following monomial term?

Divide: 90z6 `-:` 5z^2

Solution:

Given, 90z6 `-:` 5z^2

Step 1: Divide a constant terms. `90/5`=18

Step 2: Divide the variable terms. z6 `-:` z^2=`z^6/z^2` =z(6-2)=z4.

Step 3: The answer is 18z4.

Free Help Fourth Grade Math

Introduction to free help fourth grade math:

Study of basic math operations and math functions is called mathematics. Free help fourth grade math is used to learn some basic math operation. In mathematics, basic concept is arithmetic operations.

The basic arithmetic operations of mathematics are addition, subtraction, division, multiplication and placing values. The free help fourth grade math is deals with basic algebra, in the free help fourth grade math is involves a basic math operation only.  In this article we are discussing free help fourth grade math.

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Examples problem for free help fourth grade math:


Basic addition problems for free help fourth grade math:

1. Find the add value of the given numbers, using addition operation, 20 + 40 + 40

Solution:

Given numbers using addition operation for, 20 + 40 + 40

First step, we are going to add the first two numbers,

20 + 40 = 60

Then add third number with first two numbers of sum values,

60 + 40 = 100

Finally we get the answer for given numbers are 100.

2. Find the add value of the given numbers, using addition operation, 36 + 28 + 36

Solution:

Given numbers using addition operation for, 36 + 28 + 36

First step, we are going to add the first two numbers,

36 + 28 = 64

Then add third number with first two numbers of sum values,

64 + 36 = 100

Finally we get the answer for given numbers are 100.


Basic subtraction problems for free help fourth grade math:


3. Find the subtract value of the given numbers, using subtraction operation, 10 - 30 - 5

Solution:

Given numbers using subtraction operation for, 10 - 30 - 5

First step, we are going to add the first two numbers,

10 - 30 = -20

Then subtract third number with first two numbers of subtracted values,

-20 - 5 = -15

Finally we get the answer for given numbers are -15.

4. Find the subtract value of the given numbers, using subtraction operation, 6 - 12 - 6

Solution:

Given numbers using subtraction operation for, 6 - 12 - 6

First step, we are going to add the first two numbers,

6 - 12 = -6

Then subtract third number with first two numbers of subtracted values,

-6 - 6 = -12

Finally we get the answer for given numbers are -12.

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Basic multiplication problems for free help fourth grade math:


5. Find the multiply value of the given numbers, using multiplication operation, 7 * 3 * 3.

Solution:

Given numbers using multiplication operation for, 7 * 3 * 3

First step, we are going to multiply the first two numbers,

7 * 3 = 21

Then multiply the third number with first two numbers of multiplied values,

21 * 3 = 63

Finally we get the answer for given numbers are 63.

6. Find the multiply value of the given numbers, using multiplication operation, 2 * 4 * 6

Solution:

Given numbers using multiplication operation for, 2 * 4 * 6

First step, we are going to multiply the first two numbers,

2 * 4 = 8

Then multiply the third number with first two numbers of multiplied values,

8 * 6 = 48

Finally we get the answer for given numbers are 48.

Monday, April 22, 2013

Elementary Math Factorize

Introduction:

Factorization is one of the basic topics in mathematics. Factorization helps to find the factors for the given equation. Generally factorization is done in algebra equations. It is applicable only with constants and numbers. Factors generally defined as extracting numbers from the given terms. It is also defined as expressing the given numbers as a product of its factors.  Elementary math factorize involves basic factorization problems. Elementary math factorization problems are easy to solve. Elementary math factorize also involves some simple algebra problems. In this article, we are going to see about elementary math factorize.

Elementary math factorize:


Elementary math factorize example 1:

Find the factors for the given number, 24

Solution:

The factors for the given numbers are

24 = 2, 3, 4, 6, 8, 12, 24

These numbers are multiples of 24 hence these are the factors of 24.



Elementary math factorize example 2:

Find the factors for the given number, 32

Solution:

The factors for the given numbers are

32 = 2, 4, 8, 16, 32

These numbers are multiples of 32 hence these are the factors of 32.



Elementary math factorize example 3:

Find the factors for the given number, 52

Solution:

The factors for the given numbers are

52 = 2, 13, 26, 52

These numbers are multiples of 52 hence these are the factors of 52.



Elementary math factorize example 4:

Find the factors for the given number, 45

Solution:

The factors for the given numbers are

45 = 3, 5, 9, 15, 45

These numbers are multiples of 45 hence these are the factors of 45.

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Algebra math factorize:


Algebra math factorize example:

Factorize, x^2 + 5x + 6 = 0

Solution:

We need to factorize the given equation,

x^2 + 5x + 6 = 0

x^2 + 3x + 2x + 6 = 0

(x^2 + 3x) + (2x + 6) = 0

x(x + 3) + 2(x + 3) = 0

(x + 2) (x + 3) = 0

x + 2 = 0

Subtract 2 on both sides,

x + 2 – 2 = 0 – 2

x = -2.

x + 3 = 0

Subtract 3 on both sides,

x + 3 – 3 = 0 – 3

x = - 3

The factors are -2,-3.

Friday, April 19, 2013

Math Financial Equations

Introduction:

Most of the mathematical financial equations have been derived from the fundamental finance formulas which have been related to the time value of money. Some of the specific formulas that are in correspondence with the financial equations are derived using the derivatives of the fundamental formulas. Some of the mathematical finance equations include statistics, randomness and probability.

The mathematical finance equations are used to calculate and derive the answers for more complicated finance problems.


Symbols used in math finance equations:


There are various symbols that are used in the math finance equations which are listed below,
PMT represents the periodic payment
T indicates the terminal period or the last period
CF represents the flow of cash
FV indicates the future value
PV indicates the present value
rN indicates the nominal interest rate
rE represents the Effective interest rate where r = interest rate
m indicates the compounding frequency
B is used to indicate the balance
N represents the number of periods
G is to represent the rate of growth

Some basic math finance equations:


There are some of the fundamental formulas which are used to calculate the math financial equations.

The math financial equation used to calculate the number of payments is given by

N = - log (1-rFV / PMT)
log (1+r)

The equation to convert the interest rate compounding bases are given by

r2 = [(1+ (r1 / n2))n1/n2-1]n2

Here r1 indicates the original rate of interest with the compounding frequency n1, and r2 represents the stated interest rate with the compounding frequency n2.

The math financial equation which is used to calculate the future value of a single sum is given by

FV = PV (1+r) n

To calculate the future value with compounding the finance math equation is given by

FV = PV(1+(r/m))n-m

The equation used to calculate the future value of a cash flow series is given by

FV =`sum_(j-1)^n` CFj(1+r)j

The expanded net present value formula using the math financial equation is given by

NPV = `sum_(T=0)^T` CFT/ (1+r)T = CF0 + CF1/ (1+r)1 + CF2 / (1+r)2 + ... + CFT / (1+r)T

The present value of a single sum is calculated using the equation

PV = FV / (1+r) n

Thus the math financial equation which is used to calculate the present value with compounding is given by

PV = FV / (1+(r/m)) n-m

Math Measurement CM

Introduction of math measurement cm:

In mathematics, measurement is a main part. Similar to inches, centimeters, kilometers, meters, feet, yards and millimeter. This is also the basic concepts in math .Here we are going to see some example problems of measurement cm. Some times the number is also represent some standard measurement, such as meter, kilogram in math.

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Example problems of measurement cm in math:


Measurement of inches to centimeters:

1 inches = 2.54 centimeters

Example 1:

Convert 13 inches to centimeters.

Solution:

Step 1: We know that 1 inches = 2.54 centimeters.

Step 2: We need find 12 inches to centimeters.

Step 3: Multiply 12 with 2.54 = 30.48

Step 4: Therefore, 12 inches = 33.02 centimeters.



Measurement of millimeter to centimeter:

1 millimeter = 0.1 centimeters

Example 2:

Convert 45 millimeters to centimeter.

Solution:

Step 1: We know that 1 millimeter = 0.1 centimeter.

Step 2: We need find 45 millimeter to centimeter.

Step 3: Multiply 0.1 with 45 = 4.5

Step 4: Therefore, 45 millimeters = 4.5 centimeter.

Measurement of feet to centimeter:

1 feet = 30.48 centimeters.

Example 3:

Convert 12 feet into centimeters.

Solution:

Step 1: We know that 1 feet = 30.48 centimeters.

Step 2: We need find 12 feet in to centimeters.

Step 3: Multiply 12 with 30.48 = 365.76

Step 4: Therefore, 12 feet = 365.76 centimeters.


More about cm measurement in math


Measurement of yards to centimeters:

1 yards = 91.44 centimeters.

Example 4:

Convert 5 yards into centimeters.

Solution:

Step 1: We know that 1yard = 91.44 centimeters.

Step 2: We need find 5 yards into centimeters.

Step 3: Multiply 91.44 with 5 = 457.2

Step 4: Therefore,  5 yards = 457.2 centimeters.



Measurement of miles to centimeters:

1 miles = 1,60,934.4 centimeter

Example 5:

Convert 2 miles into centimeter.

Solution:

Step 1: We know that 1 miles = 1,60,934.4 centimeter.

Step 2: We need find 2 miles into centimeters.

Step 3: Multiply 2 with 1,60,934.4  = 321868.8

Step 4: Therefore, 2 miles = 321868.8 centimeters.



Measurement of meter to centimeters:

1 meter = 100 centimeters.

Example 5:

Convert 27 meter to centimeters

Solution:

Step 1: We know that 1 meter =100 centimeters.

Step 2: We need find 27 meter in to centimeters.

Step 3: Multiply 100 with 27 = 2700

Step 4: Therefore, 27 meter = 2700 centimeters.

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Measurement of kilometer to centimeters:

1 kilometer = 1,00,000 centimeters.

Example 6:

Convert 2 kilometer to centimeters

Solution:

Step 1: We know that 1 kilometer =1,00,000 centimeters.

Step 2: We need find 2 kilometer in to centimeters.

Step 3: Multiply 1,00,000 with 2 = 2,00,000

Step 4: Therefore, 2 kilometer = 2,00,000 centimeters.

These are the examples of measurement cm in math .

Wednesday, April 17, 2013

Math Percents Problems

Introduction to percentage:

In mathematics, a percentage is a way of expressing a number as a fraction of 100 (per cent meaning "per hundred" in French). It is often denoted using the percent sign, "%", or the abbreviation "pct". For example, 45% (read as "forty-five percent") is equal to `45 / 100` , or 0.45. In this article you will get help on how to find percentages with some example problems.

- Source from Wikipedia

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Help on finding percents:


To convert a fraction and a decimal to a percentage we have, multiply it by 100.

Similarly to convert a percentage to a fraction and decimal, divide it by 100.

We can express a fraction and a decimal as a percentage.

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Help on percentage problems:


Problem 1:

What is the decimal value of percentage 84%?

Solution:

84% =  ` 84 /100` = 0.84

84% is 0.84

Problem 2:

What is the decimal value of percentage 72.3%?

Solution:

72.3% = `(72.3) / 100 ` = 0.723

72.3% is 0.723

Problem 3:

How to add 89% to 23?

Solution:

89% + 23 = 0.89 + 23 = 23.89

Problem 4:

What is the 76% of 24?

Solution:

Let us take 76% as `76 /100`

76% of 24 =` 76 / 100` * 24

=  3.16

Problem 5:

In a box there are 72 peanut packets. If a girl took 60% of peanut packets, how many peanut packets did she left in the box?

Solution:

The girl took the peanut packets from the box is 60% of 72 or else `60/100` × 72

`60 / 100` × 72 = 43.2%

So the box contains 72 peanut packets and the girl took 43 peanut packets. The number of peanut packets girl left in the box is 72 – 43 = 29.
Therefore the girl left 29 peanut packets in the box.

Help on Practice problem for finding percentage:

Problem 1:

What is decimal value of the percentage  22%?

Solution:

= 0.22.

Problem 2:

What is the decimal value of percentage 61%?

Solution:

= 0. 61

Problem 3:

What is 84% of 22?

Solution:

= 18.48 is 84% of 22.

Monday, April 15, 2013

Subtraction Answer

Introduction to subtraction answer:

Subtraction is one of the four basic arithmetic operations; it is the inverse of addition, meaning that if we start with any number and add any number and then subtract the same number we added, we return to the number we started with. Subtraction is denoted by a minus sign in infix notation.

c − b = a

where minuend (c) − subtrahend (b) = difference (a). Now we see about subtraction answer.

(Source: Wikipedia)

About subtraction answer:


In the subtraction, the given parts are named as the minuend and the subtrahend and the resultant answer will be named as the difference. The Minuend which is the first number and the subtrahend is the second number. Thus, we have to subtract the number in this format only.

The Subtraction answer is nothing but the resultant of the numbers which have been subtracted. Let us see one example for the subtraction answer method.

Example:

Subtract the number 1 from 4 and give the subtraction answer.

Solution:

It can be given as (4 - 1). The Following is for the subtraction answer as follows,

4       ->Minuend

-1      ->Subtrahend

-----------------------------------

3      ->Difference

--------------------------------------

Thus, the subtraction answer or the difference can be given as 3.

Way of checking the subtraction answers:

The subtraction answers can be checked or verified by using the technique given below.

The Difference number and the subtrahend number should be added together to give the minuend number.

The above example can be checked as follows,

1       ->subtrahend

+ 3    ->difference

------------------------------

4       ->minuend

--------------------------------

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Problems for subtraction answer:


Example 1:

Subtract the numbers :(-5 – 6)

Subtraction answer:

Now we are going to subtract the numbers as follows,

(-5 – 6) = -5 + (-6) = -11.

Subtracting 6 is the same as adding a -6.

Thus, we get the subtraction answer as -11.

Example 2:

Subtract the given expressions and find the value of x in the expression:

5x = 6

3x = 2

Subtraction answer:

Now we subtract the two expressions.

5x = 6

- 3x = 2

-------------

2x = 4

---------------

Now divide the equation on both the sides we get,

x = 2.

Thus, the subtraction answer for the given expression is 2x = 4 and the value of x is 2.

Friday, April 12, 2013

Math Practice 4

Introduction:

The math practice 4 is the basic concepts involved in mathematics. Here the topic discussed are  about the usual terms in algebra like addition, subtraction, multiplication and division. Then it also solves some word problems for easy understandings so that learning math becomes simple and easy for the learners.

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Basic concepts:


The math practice 4 involves some basic concepts in mathematics. In this we are going to see about algebra in math practice 4 .They are:

Variables
Expressions
Terms
Polynomials
Equations

Example problems:


Example 1: Solve for x?

79 + 33  = x

Solution:

To find x value

79 + 33 = x

x =112

The answer x is 112

Example 2:

The number decreased by 70 is 12 times its opposite. Find the number.

Solution: First we convert the algebra word problem to a numerical form to get the solution.
The number is decreased by 70 is 12 times its opposite.
Write an equation.

x - 70 = -12x                       (Equation)

x - 70 + 70 = -12x + 70       (add 70 on both sides we get)

x + 12x = -12x +12x + 70     (add 12x on both sides we get)

11x = 70

x = 6.36

Example 3 : Solve for M?

77 + 3 = M

Solution:

77 + 3 = M

M = 80

The answer M is 80

Example 4: Solve for q?

q + 7 = 49

Solution:

To solve the p value

q = 49 – 7

q = 42


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Example 5: Solve the following system of the linear equations using the method of substitution.

x - y = -6 ,4x+8y = -48

Solution:

Step 1: Rearrange the first equation,

x - y = -6

y = x + 6

Step 2: Substitute this value for y into the second equation;

4x + 8(x + 6) = -48

Step 3: Expand and simplify the equation:

4x + 8x + 48 = -48

12x = -96

x = -8

Step 4: Substitute x back into the one of that original equations;

-8 - y = -6

y = -2

Monday, April 8, 2013

4th Grade Math Expression

Introduction of 4th grade math expression:-

In mathematics, an expression is a finite combination of symbols that are well-formed according to the rules applicable in the context at hand. Symbols can designate values (constants), variables, operations, relations, or can constitute punctuation or other syntactic entities. The use of expressions can range from simple arithmetic operations like 3+ 5 x ((-2)^7 – 3/2) . (Source: Wikipedia)

Topics involves in 4th grade math expression:-


In 4th grade math expression to study the algebra expression in following types are used in algebra expression.

Variable expression
Variable expression using word
Expression using order of operation and parentheses.

Variable expression

In 4th grade math variable expression means to form a number and word in expression like as add, plus, greater, less than, increase, decrease etc.

For Example,

287 increased by x?

287 + x

Variable expression using word

In 4th grade math variable expression using word means the expression numbers and word are shows the sentence formation like as add, plus , greater ,less than ,decrease etc

For Example,

Haley earned 92 bonus points. Marisol earned b more bonus points than Haley. Choose the expression that shows how many bonus points Marisol earned.

92+b

Expression using order of operation and parentheses

In 4th grade math expression using order of operation and parentheses means to perform the arithmetic operations as addition, subtraction, multiplication and division.

For Example,

1 + 7 × 3 – 7 = 15.

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Example problems for 4th grade math expression


Problem 1:-

Solve expression using order of operation and parentheses 2 + 4 × 5 – 10?

Solution:-

Given 2+4x5-10

= 2+4x5-10

= 2+20-10

= 22-10

= 12

Problem 2:-

Solve expression using order of operation and parentheses (468 + 638) + (134 × 761) – 875 – 632?

Solution:-

Given (468 + 638) + (134 × 761) – 875 – 632

= (468 + 638) + (134 × 761) – 875 – 632

= 1106+101974-875-632

= 103080 – 243

=  102837


Practice problems for 4th grade math expression:-

Problem 1:-

Solve variable expression for 370 added to v.

Answer:-

V+370

Problem 2:-

Solve variable expression for 28 minus w.

Answer:-

28 –w

Problem 3:-

Solve variable expression for 703 increased by z.

Answer:-

703+z

Problem 4:-

Talia earned 64 bonus points. Jones earned d more bonus points than Talia. Choose the expression that shows how many bonus points Jones earned.

Answer:-

64+d

Sunday, March 31, 2013

For Beginners Math

Introduction to beginners math:

Mathematics is the study of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions. There is debate over whether mathematical objects such as numbers and points exist naturally or are human creations. The mathematician Benjamin Peirce called mathematics "the science that draws necessary conclusions". (Source: Wikipedia)

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Example problems for beginners math:


Beginners math - Addition problem:

There are 20 passengers in train A and 15 passengers in train B. How many passengers is there altogether in the two trains?

Solution:

Passengers in train A = 20

Passengers in train B = 15

Passengers in train A + Passengers in train B

So, 20 + 15 = 35

There are 35 passengers altogether in the two trains.

Beginners math - - Subtraction problem:

A fruit whole seller had 12 cucumbers. He sold 8 cucumbers. How many cucumbers did he have left?

Solution:

The total amount of cucumbers = 12 cucumbers.

Sold strawberries = 8

Remaining strawberries =?

So, 12 – 8 = 4

He had 4 cucumbers left.

Beginners math - - Multiplication problem:

There are 9 Strawberries in each box. How many are there in 5 boxes?

Solution:

So, 9 × 5 = 45

There are 45 Strawberries in 5 boxes.

Beginners math - Division problem:

Clark bought a sack of 64 kg of flour. He has packed the flour equally into the 4 bags. How many kilograms of flour were there in each bag?

Solution:

64 ÷ 4 = 16

There were 16 kg of flour in each bag.

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Practice problems for beginners math:


1. There are 15 passengers in mini bus A and 13 passengers in mini bus B. How many passengers are there altogether in the two mini bus?

[Answer: 28]

2. A fruit whole seller had 19 sapotas. He sold 8 sapotas. How many sapotas did he have left?

[Answer: 11]

3. There are 5 oranges in each box. How many are there in 6 boxes?

[Answer: 30]

4. Jerry bought a sack of 99 kg of flour. He has packed the flour equally into the 3 bags. How many kilograms of flour were there in each bag?

[Answer: 33]

Monday, March 25, 2013

Help With First Grade Math

Introduction to help with first grade math:

In mathematics, help with first grade math is one of the important topics to understanding the basic concepts of number, measurement, algebra, and geometry. First grade math problems are use different types of arithmetic operations that are simple addition, subtraction, multiplication, and conservation. Learn the important topics of time and also it compares the length and various units of the measurements. For solving different types of problems, here we solve the different types of problems for the first grade students in an easy way. Help with first grade math problem is used to learn the basic concepts in mathematics.

I like to share this Subtraction of Fractions with you all through my article.

Help with First grade math problems:


Some example problems for help with first grade math problems are,

1. Shakespeare has 17 pencils. 12 of them are in orange color and the rest of them are red color. How many of the pencils are in red color?

Solution:  17 – 12 = 5

Answer: Red color pencils = 5

2. William ate 8 cookies and peter ate 5 cookies. How many more cookies did peter eat than William?

Solution: 8 - 5 = 3

Answer: 3 more cookies

3. Adam got 6 new shirts on his mother’s birthday. If he already had 8, how many shirts does Adam have a now?

Solution: 6 + 8 = 14

Answer: 14 Shirts

4. Anderson has to share 10 Chocolates with his friends. How many will each of them get?

Solution:

10 / 2 = 5

Answer: 5 Chocolates each

5. Jackie contains 7 cents of Licorice. If his two brothers also have same licorice means, how many of the licorice all of them have (in cents)?

Solution:

Jackie + 2 = 3

3 × 7 = 21 cents

Answer: All of them have 21 cents of licorice.

6. How many sides are on three squares?

Solution:

1 square contains 4 sides

Three square = 3 × 4 = 12 sides

Answer: Three squares contains 12 sides

7. How many sides for five rectangles are having?

Solution:

1 rectangle = 4 sides

Five rectangle = 4 × 5 = 20 sides

Answer: Five rectangles have 20 sides

8. Angelina saw 3 elephants and 2 tigers outside of the street. How many animals did Angelina see?

Solution:

3 elephants and 2 tigers

= 3 + 2 = 5 animals

Answer: Angelina saw 5 animals.

9. Lincoln have 10 pens, half of them are in red color. How many of the pens are in red color?

Solution:

Total pens = 10

Half of pens = 10/ 2 = 5

Answer: Lincoln has 5 red balls

10. How many vertices are on two triangular prisms?

Solution:

1 triangle prism has 6 vertices

Three triangle prisms = 2 × 6 = 12 vertices

Answer: Two triangle prisms have 12 vertices.

Help with First grade math problem for practice:


A. How many vertices are on 5 triangular prisms?

B. Abraham have 14 balls, half of them are in white color. How many of the balls are in white color?

C.  Lee saw 3 tigers and 4 zebra in a zoo. How many animals did lee see?

D. How many sides are on 4 squares?

E. Peter has 2 cents of Licorice. If his four brothers also have same means, how many of the licorice all of them have (in cents)?

A. 30 vertices

B. 7 balls are in white color

C. 7 animals

D. 16 sides

E. 10 cents

Thursday, March 21, 2013

All Answers to Area Math

Introduction to all answers to area math:

Area is the measure of surface occupied by an object. The standard unit for measurement of area is meter square (m2).However the areas of smaller dimensions can be expressed in mm2or cm2.The areas of large amount of dimensions can be expressed in acre or hectare. Here we are going to study about how to calculate the answer for area of the shape and its example problems. (Source from Wikipedia)

I like to share this Area Formula for a Rectangle with you all through my article.

Example problems for all answers to area math:


Example: 1

Find the area of the rectangle with base 8 meter and height is 7 meter

Solution:

We know the formula for find the area of the rectangle is base *height

Area = 8 *7

Area = 56 meter square

math answer:

The area of the given rectangle is 56 meter square.

Example: 2

Find the area of triangle with base 12 meter and height is 9 meter

Solution:

We know the formula for area of triangle,

Area =`1/2 `  (base *height)

Here base = 12 meter and height = 9 meter substitute the above formula we get

Area = `1/2 ` (12 * 9)

Area =`1/2` (108)

= `108/2`

= 54 meter square

math answer:

The area of the triangle is 27 meter square

Understanding free online math solver is always challenging for me but thanks to all math help websites to help me out.

Example problem for all answers to area math: 3


A cylinder with radius 15 cm and height 3 cm calculate the surface area of the cylinder.

Solution:

Cylinder radius is (r) = 15 cm

Height of the cylinder (h) = 3cm

Already we know the formula for finding the surface area of the cylinder is

A = 2`pi` r2 + 2 `pi` r h

Here 2 `pi ` r is common so take out

A= 2 `pi` r (r+h)

Substitute the height and radius of the cylinder in the above formula we get

A= 2 * `pi` * 15 (15+3)

Simplify the above expression

Area = 2 * 3.14 *15 (18)

Area = 94.2 *18

Area = 1695.6

math answer:

Area of the given cylinder = 1695.6 cm square

Monday, March 18, 2013

Prime Numbers in Math

Introduction to Math prime numbers:

In mathematics, a prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself. The first twenty-five prime numbers are:

Prime Numbers:- 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

Condition: - If x is the prime number then the next factors of the number x is 1 and X.                                                                                                                                                                                                                               - Source from Wikipedia


Prime numbers in math:


To finding a prime number up to 100 means we can calculate directly but we need to find above hundred means we have follow the shortcut method.

For example:
Check if 131 is a prime number.

Step 1:

Now we have to take Square root for 131 = 11.44
Now rounding the value 11.4 to the nearest big whole number. We can write 11.4 as 12.

Step 2:

Then find the Prime Numbers below 12. The factors up to 12 are 2, 3, 5, 7, 1

Step 3:
The given number 131 is not divisible by 2, 3, 5, 7 and 11

131 is divisible by and the number itself.
So the number 131 is considered as prime number.


Example problems for math prime number:


Problem 1:

Find whether the number 53 is prime number or not?

Solution:

The given number 53 is a prime number. Why means it includes two factors 1 and 53 only. So the number 53 is a prime number.

Problem 2:

Find whether the number 79 is prime number or not?

Solution;

The given number 79 is divisible by one and itself only. So it is called as prime number.

Problem 3:

Find whether the number 39 is prime number or not?

Solution:

The given number 39 has more than two factors. That is 1, 6, 13 and 39. Hence the given number 39 is not a prime number.

Problem 4:

Find whether the number 434 is prime number or not?

Solution;

The given number 434 has more than two factors. That is 1, 2, 7, 31, 217, and 434. Hence the given number 434 is not a prime number.

Problem: - 5

Find whether the number 638 is prime or not?

Solution:

The given number is 638 has divided by two. So the factors for 638 are 1,2, 11, 29,    319 and 638. Hence 638 is not a prime number.

Practice problem for math prime numbers:

Problem 1:

Find whether the number 43 is prime or not?

Solution:

The given number 43 is a prime number.

Problem 2:

Find whether the number 126 is prime or not?

Solution:

The given number 126 is not a prime number.

Wednesday, March 13, 2013

Answer Math Questions For Me

Introduction to answer math questions for me:

Answering math questions is a simple one. The math terms for whom it is well known can answer the math questions. The math question involves the various topics in which the each topic can be solved through the different manner. The math questions may have the various methods for the solving purpose but the solution of the question may be the same in whatever method the particular problem is made to solve. I like to share this Solve Fractional Equations with you all through my article.


Answer math questions for me:


The answer math questions are done through the well trained persons who have the certificates under the math. The math can be taught under various methods, it is better to solve in the known steps and also preferring the easy steps for solving the questions. The math questions should be read more than one times to have the cute understandings on the particular topics. These math answers would helps you to have the quite understanding on the methods mentioned below.

Understanding Dividing Fractions Calculator is always challenging for me but thanks to all math help websites to help me out.

Examples for math questions for me:


Example 1:

What is -6+ (-2)?

From above: (- )+(-) becomes a negative sign.

-6+ (-2) = -6 - 2

Answer: -6+ (-2) = -8.

Example 2 : What is -5+ (-2)?

+ (-) gives a negative sign.

-5+ (-2) = -5 - 2 = -7.

Answer: -5+ (-2) = -7.

Example 3: What is -6- (+3)?

- (+) becomes a negative sign.

-6- (+3) = -6 - 3=-9

Example 4: solve 1/3 + 2/6 fraction problem:

=   1/3 + 2/6

Having common denominator has 6 then multiply 3 with 2 then we can have 6 has the common denominator. so multiply 2 with 3 then it becomes 6.

=   2/6 + 2/6

=   4/6

Answer :  2/3.

Example 5: Solve 2/4 + 1/4 fraction problem:

= 2/4 + 1/4

Having common denominator has 4 simply add the numerators  = (2 + 1)/4

= 3/4

Answer: 3/4.

Example 6: Solve 12/5 + 5/6

= 12/5 + 5/6

= [(12 X 6) + (5 X 5)]/ 30

= [72 + 25]/30

= 97/30

Answer: 97/30

Example 7: solve 8/7 + 5/4

= [(8X 4) + (5 X 7)]/4 X 7

= [(32) + (35)]/28

= 67/28

Answer: 67/28

Example 8:

Heights in cms of ten people are:

126, 145, 150, 157, 149, 136, 166, 129, 143, 134

Solution:

Mean: sum of all values/total numbers

Mean= 1435/10

=143.5

Answer: 143.5

Example 9:

The highest scores of the five players in twenty twenty are:

198,192,182,190,179.

Solution:

Mean = sum of all values/total numbers.

= 941/5

Answer: 188.2

Example 10:

Heights in cms of thirteen players are:

110,115,120,125,130,135,150,145,150,155.

Solution:

Mean: sum of all values/total numbers

Mean = 1335/10

= 133.5

Answer: 133.307

Example 11:

The highest scores of the ten players one day are:

198,195,192,190,186,194,182,180,179,178.

Solution:

Mean = sum of all values/total numbers.

= 1874/10

Answer: 187.4

Tuesday, March 12, 2013

Statistics Free Course

Introduction to Statistics Free Course:
Statistics is the science of making effective use of numerical data relating to groups of individuals or experiments. It deals with all aspects of this, including not only the collection, analysis and interpretation of such data, but also the planning of the collection of data, in terms of the design of surveys and experiments.

Let us study statistics course freely.


Statistics Free Course - Basics concepts:


Arithmetic mean:

The arithmetic mean in statistics is the average of data in arithmetic. A set of data which is divide by sum of observations and number of observations in the given data.

                                       Sum of observations

Arithmetic Mean = --------------------------------------

                                        Number of observations

Median:

The median is a set of numbers which the middle number and find the set of numbers in them. Then arrange the number in order to select the middle number.

Mode:

It is a set of numbers which occurs frequently in the set of data and no number can occur more than once.

Standard Deviation:

The standard deviation is an arithmetical figure which can spread and variability the data. It has the root mean square of values in their arithmetic mean. Is this topic Sum of Two Random Variables hard for you? Watch out for my coming posts.


Examples for Statistics Free Course:


The followings are the examples for statistics free course.

1. Find the arithmetic mean of weights for 6 peoples in kilograms are 45, 18, 65, 82, 78, 33, 71, and 60.

Solution:

                      Sum of total number

Mean = -----------------------------------

                          Total number

                 45 + 18 + 65 + 82 + 78 + 33 + 71 + 60

=  -------------------------------------------------------------------------
                                        10

     452

= ----------
      10

= 45.2

2. Find the median of 12, 10, 24, 18, 45, and 30.

Solution:

Arrange the data in ascending order as 10, 12, 18, 24, 30 and 45.

N = 6

Since n is even, median = `1 / 2` [nth/2 item value + (`n / 2` + 1)th item value]

= `1 / 2` [6th item value + (`6/2` + 1)th item value]

= `1 / 2` [3rd item value + 4th item value]

= `1 / 2` [18 + 24]

= `1 / 2` * 42

= 21

3. Find the mode of 90, 35, 80, 72, and 35.

Solution:

35 are repeated twice.

Mode =35

4. Find the Standard deviation for 2, 5, 1, 9 and 8.

Solution:

Step 1:

To calculate the mean and deviation.

X = 2, 5, 1, 9, 8

M = `(2 + 5 + 1 + 9 + 8) / 5`

= `25 / 5`

= 5

Step 2:

To find the sum of (X - M) 2

9 + 0 + 16 + 16 + 9 = 50

Step 3:

Where N = 5, the total number of values.

Find N - 1.

5 - 1 = 4

Step 4:

To locate Standard Deviation by the method.

√50 / √4 = `7.07 / 2`

= 3.53

Monday, March 11, 2013

Algebra ii Math

Introduction to  algebra ii math:

Algebra ii is one of the important categories in mathematics.

Algebra ii contains the following topics

Solving equations and inequalities

Graphs and functions

Polynomials and factoring

Fractional Expressions

Powers and roots

Complex numbers

Quadratic equation

In this article we shall discuss about the some example problems on algebra ii maths. I like to share this Fractional Coefficients with you all through my article.


Problems on solving equations in algebra ii maths:

X+2y=5

2x-y=10

Solution:

Step 1: To make anyone of the variable as common coefficients

From the above problem multiply the equation 2 by 2 we get,

X+2y=5

4x-2y=20

------------

5x=25

Step 2: Divide by 5 on both sides

5x/5 =25/5

X=5

Step 3: Substitute the value of x in first equation

X+2y=5

5+2y=5

Step 4: Subtract 5 on both sides,

5+2y-5=5-5

2y=0

Y=0

Problems on polynomials and factoring in algebra ii maths:

Factor: x^2-5x-150

Solution:

Step 1: The above equation is quadratic equation because it has the highest degree of 2

Multiply the coefficient of x^2 and constant term

1*-150 = -150

Step 2: Find the factor for the product term. Sum of the factor is equal to coefficients of x

-150 = -15*10

-15+10 = -5

Step 3: Now the equation is written as,

x^2-15x+10x-150

Take the common term outside,

x(x-15)+10(x-15)

(x+10) (x-15)

Understanding Inverse Function Definition is always challenging for me but thanks to all math help websites to help me out.

Problems on fractional expressions in algebra ii maths:


(x+5)/(y-10) + (2x+3)/(y-2)

Solution:

Here the denominators are different. To make the common denominator take the LCD of (y-10) and (y-2).       LCD= (y-10)(y-2)

(x+5)/(y-10) + (2x+3)/(y-2)

(x+5)/(y-10) * (y-2)/(y-2) + (2x+3)/(y-2) * (y-10)/(y-10)

(x+5)(y-2)/(y-10)(y-2) +(2x+3)(y-10)/(y-2)(y-10)

((x+5)(y-2)+ (2x+3)(y-10)) /(y-10)(y-2)

(xy-2x+5y-10)+(2xy-20x+3y-30) / (y-10)(y-2)

(3xy-22x+8y-40) / (y-10)(y-2)

Problems on quadratic equation in algebra ii maths:

Solve the quadratic equation by factoring method and find roots?

2x^2+x-10=0

Solution:

Step 1: Multiply the coefficient of x^2 and the constant term,

2*-10 =-20 (product term)

Step 2: Find the factors for the product term

-20 ---- > -5 *4 = -20 (factors -5 and 4)

-5+4 = 1 (1 is equal to the coefficient of x)

Step 3: Split the coefficient of x as factors

2x^2+x-10=0

2x^2-5x+4x-10=0

Step 4: Taking the common term x for the first two term and 2 for the next two terms

x(2x-5) +2(2x-5) =0

(x+2) (2x-5)=0.

Now set (x+2) =0; x=-2;

(2x-5)=0; x=5/2.

The roots are x=-5/2 and -2.

Problem Solving Math

Introduction to problem solving math:

Problem solving is a mental process and is part of the larger problem process that includes problem finding and problem shaping. Considered the most complex of all intellectual functions, problem solving has been defined as higher-order cognitive process that requires the modulation and control of more routine or fundamental skills. Problem solving occurs when an organism or an artificial intelligence system needs to move from a given state to a desired goal state.                                                                                                                                      Source wikipedia

Problem solving math examples:
Solving math problem 1

Method 1

Add the two fractions `15/64` and `14/64`

Solution:

The given two fractions `15/64` and `14/64`

=`15/64` +`14/64`

= `(15+14)/64`

=`19/64`

This can be simplified has

Answer=0.2968

Solving math problem 2

Add the two fractions `44/6` and `26/6`

Solution:

The given two fractions `44/6` and `26/6`

=`44/6` +`26/6`

=`(44+26)/6`

=`70/6`

=17.66

Answer=17.66

Solving math problem 3

Solve 3x = 2x+18

Solution:

Here the addition operations involved in algebraic expression.

From the given problem 3x = 2x+18

Subtract 2x on both sides,

3x-2x=2x+18-2x

x =18

Answer  x=18

Solving math problems: 4

Find the volume of sphere with diameter 16 meter?

Solution:

Volume of sphere = `4/3` *pi*radius 3.

We know that diameter = 16 m. So we know that radius = diameter/2 =`16/2` =8 m

Plug the radius value in to the formula.

Volume of sphere = 4/3 *3.14*83

So, we get

=2143.57 m3

Answer 2143.57 m3

Understanding Surface Area of a Pyramid is always challenging for me but thanks to all math help websites to help me out.

Additional solving math problems:



Solving math problems: 5

Find out sixty five percentage of fifty six.

Solution:

= 65 * 56/100 (56 multiply with 65)

= 3640/100; (divide by 100)

= 36.4%

Answer is 36.4%.

Solving math problems: 6

Find out seventy nine percentage of fifty seven.

Solution:

= 79 * 57/100 (57 multiply with 79)

= 4503/100; (divide by 100)

Answer= 45.03%

Solving math problems: 7

Find the difference of two mixed number 8`1/3` and 9`1/3`

Solution:

The given mixed numbers are 8`1/3` and 9`1/3`

Initially to perform any operations on mixed numbers we must convert it to fraction

8`1/3` in fraction

Multiply 8 and 3 and add with 1

8`1/3` =` (24+1)/3` =`25/3`

9`1/3` in fraction

Multiply 9 and 3 and add with 1

9`1/3` = `(27+1)/3`

=`28/3`

8`1/3` -9`1/3` =`25/3` -`28/3`

=`(25-28)/3`

=-`3/3`

= -1

Answer:  -1

Thursday, March 7, 2013

Number Word Math

Introduction to Number Word Math:

The numbers are the basic source of math. The numbers can be written in many several forms such as word form, expanded form, and standard form and also in place value form. The word form can be written for the numerals or numbers in English words. For example: 1 can be written as one, etc in math. The numbers are the symbolic representation or abstract object of math. Let us see about the numbers in word form in this article. I like to share this Complex Number Calculator with you all through my article.


Representation of Numbers in Word Form


The numbers can be classified into 1 to infinity. Those numbers can be written in words such as:

Counting of Word Form from 1 - 10 for Numbers in Math:

1 – The number 1 can be written as one.

2 – The number 2 can be written as two.

3 – The number 3 can be written as three.

4 – The number 4 can be written as four.

5 – The number 5 can be written as five.

6 – The number 6 can be written as six.

7 – The number 7 can be written as seven.

8 – The number 8 can be written as eight.

9 – The number 9 can be written as nine.

10 – The number 10 can be written as ten.

Counting of Word Form from 11 - 20 for Numbers in Math:

11 – The number 11 can be written as eleven.

12 – The number 12 can be written as twelve.

13 – The number 13 can be written as thirteen.

14 – The number 14 can be written as fourteen.

15 – The number 15 can be written as fifteen.

16 – The number 16 can be written as sixteen.

17 – The number 17 can be written as seventeen.

18 – The number 18 can be written as eighteen.

19 – The number 19 can be written as nineteen.

20 – The number 20 can be written as twenty.


Other Word Forms for Numbers in Math


Counting of Word Form from 21 - 30 for Numbers in Math:

21 – The number 21 can be written as twenty-one.

22 – The number 22 can be written as twenty-two.

23 – The number 23 can be written as twenty-three.

24 – The number 24 can be written as twenty-four.

25 – The number 25 can be written as twenty-five.

26 – The number 26 can be written as twenty-six.

27 – The number 27 can be written as twenty-seven.

28 – The number 28 can be written as twenty-eight.

29 – The number 29 can be written as twenty-nine.

30 – The number 30 can be written as thirty.

Understanding the prime numbers from 1 to 100 is always challenging for me but thanks to all math help websites to help me out.

Problems to Practice in Number Word Math


Example 1:

Write the given number in words?

748

Solution:

Let us write the number 748 in words like,

748 = seven hundred and forty-eight.

Example 2:

Write the given number in words?

93572

Solution:

Let us write the number 93, 572 in words like,

93, 572 = ninety-three thousand five hundred and seventy-two.

Example 3:

Write the given number in words?

403507820

Solution:

Let us write the number 403507820 in words like,

403, 507, 820 = four hundred and three millions, five hundred and seven thousands, eight hundred and twenty.

Math Word Method

Introduction of math word:

In mathematics, especially in the area of abstract algebra known as combinatorial group theory, the word problem for a recursively presented group G is the algorithmic problem of deciding whether two words represent the same element. Although it is common to speak of the word problem for the group G strictly speaking it is a presentation of the group that does or does not have solvable word problem.(Source: Wikipedia)

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Math word problems methods:


Math word problems method 1

Twelve years ago, Morgan’s mother was four times older than her daughter. After 12years, the Morgan mother will be twice older than daughter. The present age of Morgan is:

Sol: Let Morgan’s age 12 years ago be x years.

Morgan mother’s age 12 years ago = 4x

(4x+12)+12=2(x+12+12)

x=12

Present age of Morgan= (x+12) = 24years

Answer.24 years

Math word problems method 2

On the first exam of the semester, kisans scored a 75. On the last exam of the semester, kisan scored 95% By what percent did kisan's score improve?

Solution

In first test kisan got 75

In last test he got 95.

% increase in test `( 75(x+100))/100` =95

0.75X+75=95

0.75x=95-75

0.75x=20

x=`20/0.75`

=27%

Answer:= 27%

Math word problems method 3

Orton and Victoria agree to meet in Chicago for the weekend. Orton travels 114 miles and Victoria travels 96 miles. If Orton s rate of   speed is 6mph faster than Victoria ’s then at what rate of speed does Orton travel?

Solution

Take Victoria’s speed =x,

Distance = 96 miles

Then Orton’s speed = x+6,

Distance =114 miles

Distance/speed = time, here time is constant.

Now

`114/(x+6) ` =` (96/x)`

Cross multiply on both sides

114(x)=96(x+6)

114x=96x+576

Subtract 96x on both sides

114x-96x=96x-96x+576

18x=576

Divide by 18 on both sides

`(18/18)x` =`576/18`

We get

x=32 mph

Victoria’s speed=32 mph

For Orton speed= 32+6 =38 mph

Math word problems method 4

The diameter of the driving wheel of a car is 190 cm. How many revolutions per min must the wheel make in order to keep a speed of 75 kmph?

Solution

Distance to be covered in 1 min = `(75*1000)/60` m

=1250m

Circumference of the wheel =2 `pi` r

Radius of the driving wheel = diameter of the driving wheel `/2`

=`190/2`

=95

(2 * `22/7` * 0.95)m=5.966m.

So, Number of revolutions per min   =  `1250/5.966`

=210.

Answer = 210 rpm

I have recently faced lot of problem while learning Area of Hexagon, But thank to online resources of math which helped me to learn myself easily on net.

Practice problem for math word method


Find the cost per pound of a coffee mixture made from 7 lb of coffee that costs $8.20 per pound and 11 lb of coffee that costs $6.50 per pound

Answer ;$7.16

Monday, March 4, 2013

Alternative Activity Math

Introduction to alternative activity math:

Activity learning theory is a psychosomatic meta-theory average by extraction within Vygotsky’s educational chronological phychology. organizer be Alexei N.Leont’ev, along with Sergei Rubinshtein required toward recognize person behavior while composite, generally positioned phenomenon with depart further than phychoanalysis with behaviorism. that develop into individual of main psychosomatic advance within the earlier organism extensively utilize during mutually hypothetical with functional psychology, into district such like education. Having problem with Sum of Binomial Random Variables keep reading my upcoming posts, i will try to help you.


alternative activity math:


Alternative activity theory while those appoint with interrelate by their atmosphere, manufacture of apparatus consequences. These apparatus are exteriorized structure of psychological method, with as these psychological procedure are noticeable in apparatus, they develop into further willingly available with transmissible to new group, fetching constructive for public communication.

Please express your views of this topic List of Composite Numbers to 100 by commenting on blog.

Developments in alternative activity math theory:

Activity learning theory is forceful. It know how to be utilize through a diversity of regulation to recognize the method populace proceed.

Scandinavian alternative activity math theory

This most important instruct of consideration request to combine with enlarge thought as of Vygotsky's Psychology as well as Leont'ev's activity theory such like Cognitive knowledge.

Systemic-structural alternative activity math theory

A collection of Russian activity theorists functioning within the scheme - cybernetic institution begin to distribute and production through during person issue along with ergonomics as well as, recently, person processor communication.

Beneath the rubric of structural activity theory, correspond toward a present mixture in activity theory that pass mutually the scheme structural thread of the institution by conclusion with technique as of cognitive psychology.

The expansion of theory contain be specially leaning to the psychoanalysis with plan of the essential fundamentals of individual employment motion: responsibilities, technique. SSAT include urbanized method for together the quantitative explanation of occupation activity.

Applications to design

Activity theory know how to be utilize to give a structure for notify and appraise plan

In a structure resulting as of activity math theory, some charge, know how to be busted behind into events, that are additional subordinate keen on process. In a plan circumstance, by these group know how to give the exclusive by an considerate of steps essential used for a customer to take away a charge.

Sunday, March 3, 2013

Answer Math Question Now

Introduction to mathematics:

Mathematics is the study of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics is used throughout the world as an essential tool in many fields, including natural science, engineering, and medicine. (Source: From Wikipedia). Now, we are going to see some of the question and answer in mathematics. I like to share this What are Variables? with you all through my article.


Math questions and answers:

Example question 1:

Solve for the variable x: 2x + 3 = 5

Solution:

2x + 3 = 5

Subtract 3 on both sides of the equation

2x + 3 – 3 = 5 – 3

2x = 2

Now, divide by 2 on both sides of the equation

2x / 2 = 2 / 2

x = 1

So, the answer is x=1.

Example question 2:

Find the value of the expression: xy+2x+3yz when x=1, y=0 and z=2.

Solution:

xy + 2x + 3yz

Now, substitute the value of x, y and z in the expression

xy + 2x + 3yz = 1(0) + 2(1) + 3(0)(2)

= 0 + 2 + 0

= 2

So, the answer is 2.

Understanding Pythagoras Theorem is always challenging for me but thanks to all math help websites to help me out.

Additional questions and answers in maths:


Example question 3:

The perimeter of the floor of a rectangular hall is 26 m. Its length is 8 m. Find its area.

Solution:

To determine the area we should know the length and breadth of a rectangle. So, we should find the breadth from the perimeter.

2 length + 2 breadth = perimeter

2 × 8 + 2b = 26

16 + 2b = 26

i.e. 2b = 26 – 16

2b = 10

b =10 / 2 = 5

Now the area of the rectangle A = l b

= 8 m × 5 m

= 40 sq.m.

So, the answer is 40 square meter.

Example question 3:

In a right triangle the length of the base is20 cm and the height is 25 cm. Find its area.

Solution:

Let b = 20 cm and h = 25 cm

Now, we know the formula,

Area of the right triangle, A = (1 / 2)*b*h

= (1 / 2) × 20 cm × 25 cm

= 250  sq.cm

So, the answer is 250 square cm.

Example question 5:

The mean marks in mathematics for a class is 42. If there are 50 pupils in the class find the total marks scored by them in mathematics.

Solution:

Total marks / number of pupils = mean

Total marks = mean × number of pupils

= 42 × 50

= 2100.

So, the answer is 2100 marks.

Tuesday, February 26, 2013

Math Practice Addition

Introduction for math practice addition:

Addition is a mathematical operation that represents combining collections of objects together into a larger collection. It is signified by the plus sign (+). For example, there is 3 + 2 apple, meaning three apples and two other apples, which is the same as five apples. Therefore, 3 + 2 = 5. Besides counts of fruit, addition can also represent combining other physical and abstract quantities using different kinds of numbers: negative numbers, fractions, irrational numbers, vectors, decimals and more. I like to share this Positive and Negative z Score Table with you all through my article.

Performing addition is one of the simplest numerical tasks. Addition of very small numbers is accessible to toddlers; the most basic task, 1 + 1. In primary education, children learn to add numbers in the decimal system, starting with single digits and progressively tackling more difficult problems. (Source: Wikipedia)


Math addition example problems:


Problem 1:

John has 900 dollars in his checking account. He received from his job a check for 1,300 dollars and deposits the amount in his checking account. How much money does he have in his checking after the deposit?

Solution:

The fact of receiving money from his job is a gain. Therefore, we need to perform addition.

1300
900 (+)
-------
2200
--------
Total amount in checking account = 900 + 1300 = 2200 dollars.

Problem 2:

Peter sells ice cream for a living. On Monday his revenue was 250 dollars. On Tuesday, his revenue was 120 dollars. Finally, on Wednesday, his revenue was 60 dollars. How much is Peter's revenue so far?

Solution

Peter is experiencing a gain in revenue. Therefore, we use addition.

250
120
60 (+)
------
430
-------
Peter's revenue = 250 + 120 + 120 = 430 dollars

Problem 3:

Eiffel Tower is about 1123 feet high. The Statue of Liberty along with its foundation and pedestal is about 350 feet. If you could put the Statue of Liberty on top of the Eiffel Tower, how high up in heaven will the two monuments reach?

Solution:

The situation above is a combination of parts to form a whole. Therefore, we use addition.

1123
350 (+)
-------
1423
--------
Two monuments reach = 1123 + 350 = 1423.

Understanding What are Rational Numbers? is always challenging for me but thanks to all math help websites to help me out.

Math practice problem for addition:


Math practice problem 1:

Your teacher has graded thirty-seven math tests. There are twenty-six still left to grade. How many math tests are there altogether?

Answer: 63 tests

Math practice problem 2:

There are sixteen books on a bookshelf. Twenty one books were borrowed by students. How many books were there altogether?

Answer: 37 books

Math practice problem 3:

There are thirty two pencils in a drawer. The children have already taken twenty-five of them to do their homework with. How many pencils were there in total?

Answer: 57 pencils

Monday, February 25, 2013

Answer Math Teasers

Introduction to Answer math teasers:

Math teasers are brain teasers form math and answers for the given brain teasers. Answers math teasers are challenging problems from math that gives a mind work. The difficulty of the problem make the students think more about the problems. Like the muscles which need exercises to keep in shape, brain teasers work as a exercise for keeping our mind sharp. Let us see answers math teasers, that is brain teasers from math. I like to share this pre algebra answers with you all through my article.


Answer math teasers:


Example 1:

Madison is twice as good a workman as Major and together they finish a piece of work in 18   days. In how many days will Madison alone finish the work?

Solution:

(madison 1 day’s work): (major’s 1 day’s work) = 2:1.

(Madison + major’s) 1 day’s work = `1/18` .

Divide the `1/18` in ratio of  2:1.

Therefore madison’s 1 day’s work = `(1/18 * 2/3)` = `1/27` .

Hence, Madison alone can finish the work in 27 days.

Example 2:

Dace and Ajay work together can dig a ditch in 8 hrs. dace alone can dig it in 12 hrs. In how many hours, Ajay alone can dig such a ditch?

Solution:

(dace +Ajay)’s one hour’s work =`1/8` ,   dace’s one hour’s work =`1/12`

Therefore, ajay’s one hour’s work = `(1/8-1/12)` =`1/24` .

Hence, Ajay alone can dig the ditch in 24 hours.

Answer math teasers:


Example 3:

Jack started a business by investing 36000 dollars. After 3 months walker joined him by investing  36000 dollars Annual profit of both is  37100 dollars, find the share of each?

Solution:

Ratio of jack’s  vs walker capitals= 36000*12 : 36000*9  =  4:3

Jack’s share=(37100*4/7 ) = 21200 dollars.

Walker share=(37100*3/7)  = 15900 dollars.

Example 4:

Rad, jack and walker start a business each investing  20000 dollars After 5 months Rad withdrew  5000 dollars, jack withdrew 4000 dollars and walker invests  6000 dollars more. Total profit is  69,900 dollars was got at the end of year. Find  each ones share.

Solution:

Ratio of the capitals of Rad, jack and walker

= (20000*5+ 15000*7) : (20000*5+16000*7): (20000*5+26000*7)

=205000: 212000 : 282000 = 205:212:282

Therefore,  Rad’s share =  ( 69900*205/699) = 20,500 dollars

Jack’s share  =  (69900*212/699)  = 21200  dollars

Walkers’s share   =  (69900*282/699)  =  28200 dollars

Sunday, February 24, 2013

Math Skills Test Practice

Introduction to math skills test practice:
In this article we discuss math skills test practice problems and answer in simpler ways that really make sense for the students. In this article we are going to discuss math skills test practice problem for algebra, geometry, number works, and measurements. In everyday life we are using mathematical concepts often. Math skills test practice problems are easy to solve, this makes students understand. When a math skills practice problem is solved in the easiest way, then that will really makes sense to all peoples. Having problem with Rules of Partial Fractions keep reading my upcoming posts, i will try to help you.


Solving problems on math skills test practice:


Problem 1:

A square has an area of 36 square centimeters. What is the length of each of its sides?

Solution:

The area of the square= (side)^2

Area =side^2

36 =side^2

Side = 6cm

Problem 2:

To solve for 10x+6 = 0

Solution:

Step 1: Given equation is 10x +6 = 0

Step 2: Subtract the 6 on both sides

10x +6-6 = 0-6

Step 3: 10x = -6

Step 4: Divided by 10 on both sides

10x/10 = -6/10

Step 5: x = -0.6

Problem 3:

To find the area of a trapezoid having bases 13 cm and 7cm and a height of 9cm?

Solution:

The area of the trapezoid = h/2*(b1+b2)

=9/2(13+7)

=4.5(20)

=90cm

The area is 90cm.

Example 4 :

Convert 378.6 cm into metre

Solution:

Here the conversion is from centimetre to metre. i.e. from lower unit to higher unit.

100cm = 1m.

Hence 378.6cm =378.6/100 m

= 3.786 m (shifting the decimal two digits to the left)

Please express your views of this topic Find Derivative by commenting on blog.

Practices problems on math skills test practice:

Practice problem 1:

A square has an area of 64 square centimeters. What is the length of each of its sides?

Answer: side 8 cm

Practice problem 2:

Solve for 5x +5 = 5

Answer :0

Practice problem 3:

To find the area of a four-sided figure having a base of 30cm and a corresponding height of14cm?

Answer : 420cm

Practice problem 4:

Convert 40.1735 km into metre.

Answer: 40173.5 m

Thursday, February 21, 2013

Math Subtraction Word problems

Introduction to math subtraction word problems:

Subtraction is one of the four basic arithmetic operations; it is the inverse of addition, meaning that if we start with any number and add any number and then subtract the same number we added, we return to the number we started with. Subtraction is denoted by a minus sign in infix notation. I like to share this Y Intercept Calculator with you all through my article.

c − b = a

Here minuend (c) − subtrahend (b) = difference (a).  Here we are going to see some solved math subtraction word problems and give some practice math word problems for subtraction.

(Source: Wikipedia)


Examples of math subtraction word problems:


Subtraction word problems:

Jessica has 1160 beads. 624 beads are red and the rest are blue. How many blue beads does she have?
Solution:

Jessica has 1160 beads,

624 beads are red and the rest are blue,

1160 – 624 = 536

She has 536 blue beads.

2. James and Ken donated $2400 to a charitable organization. Ken donated $650. How much did James donate?

Solution:

James and Ken donated $2400 to a charitable organization

Ken donated $650.

2400 – 650 = 1750

James donated $1750

3. There are twenty-five magazines stacked up on a bookshelf and a desk. Fifteen of them are on the desk. How many magazines are there on the bookshelf?

Solution:

There are twenty-five magazines stacked up on a bookshelf and a desk.

Fifteen of them are on the desk

25 – 15 = 10

Answer: 10 magazines

Having problem with how to do multiply fractions keep reading my upcoming posts, i will try to help you.


Practice math subtraction word problems:


1. There were forty-six birds in a tree, but fourteen of them flew away. How many birds are left in the tree?

Answer: 32 birds

2. There were fifty-seven employees working in an office building. Twenty of them left to go out to lunch. How many employees were left in the building?

Answer: 37 employees

3. Jordan made twenty-six cookies. If he already gave twelve to friends, how many does he have left?

Answer: 14 cookies.

4. The pet store had thirty-six bags of bird feed. Twenty have been eaten. How many bags of bird feed are left?

Answer: 16 bags

Monday, February 18, 2013

How to Solve Metric Conversions

Introduction to how to solve metric conversions:

The Metric Conversions are an international decimal system of measurement, which is the common system of measuring units used by most of the world. It exists with different choices of fundamental units, though the choice of base units does not affect its day-to-day use. Different variants have been considered the metric conversions. Metric units are widely used around the world for personnel, commercial and scientific purposes. The metric conversions are an easiest method to convert one unit from another unit. I like to share this Arithmetic and Geometric Series with you all through my article.


Problems for how to solve metric conversions

We can convert one form of Metric unit into another unit with the simplest calculation. Following example problems show, how to solve the Metric Conversions.

Problem 1: Convert 100 meter into feet

Sol :              1 meter is equal to 3.28 feet. Then,

100 meter = 100 x 3.28

100 meter = 328 feet

Problem 2: Convert 10 feet into centimeter.

Sol:              1 feet is equal to 30.48 centimeter. Then,

10 feet = 10 x 30.48

10 feet = 304.8 centimeter

Problem 3: Convert 25 hours into Minute

Sol :              1 hour is equal to 60 minute. Then,

25 hours = 25 x 60

25 hours = 1500 minute

Problem 4: Convert 15 cubic millimeter into cubic centimeter

Sol :              1 cubic millimeter is equal to 0.001 cubic centimeter. Then,

15 cubic millimeter = 0.001 x 15

15 cubic millimeter = 0.015 cubic centimeter

Problem 5: Convert 4 gallon of liquid into ounce.

Solution:

1 gallon of liquid is equal to 128 ounce of liquid. Then,

4 gallon = 128 x 4

4 gallon = 512 ounce

Problem 6: Convert 25 gallon into liter.

Sol :              1 gallon is equal to 3.785 liter. Then,

25 gallon = 3.785 x 25

25 gallon = 97.635 liter

Problem 7: Convert 60 kilometer in hectometers

Sol :              1 kilometer is equal to 10 hectometers. Then,

60 Kilometer = 10 x 60

60 Kilometer = 600 hectometers

Problem 8: Convert 150 centigram into kilogram.

Sol :              1centigram is equal to 0.00001 kilogram. Then,

150 centigram = 150 x 0.00001

150 centigram = 0.0015 Kilogram

Understanding online tutor statistics is always challenging for me but thanks to all math help websites to help me out.

Practice Problems on How to Solve Metric Conversions

Problem 1: Convert 5 liter into gallon

Answer: 5 liter = 1.32 gallon

Problem 2: Convert 10 kilometer into mile

Answer: 10 kilometer = 6.213 mile

Sunday, February 17, 2013

Answer Math Problems

Introduction about Math Home Work Help:

Math Home Work Help is very simple and easier. Math Home Work Help is nothing but learning about how to work out the homework problems in online with the help of the tutors. Tutors help with homework problems with step by step explanations to the students. The students can freely interact with the tutors and ask their doubts to complete their homework. By the process of online tutoring the students learn a lot from the tutors about their homework problems. Here are some of the sample and model problems about Math Home Work Help. Please express your views of this topic tutoring for math by commenting on blog.


Math Home Work Help


1. Add 324 + 261

Tutor Solution

3 2 4                Add the ones digit 4 + 1 = 5
2 7 1 +            Add tens digit 2 + 7 = 9
----------             Add hundred’s digit 3+ 2 = 5
5 9 5
----------
2.  Multiply 6 2 8 * 7

6 2 8            multiply the multiplicand628 with multiplier 7

7 x         multiply 7 with 8 = 56.

----------          multiply 7 with 2 = 14 + 5 = 19

4 3 9 6           multiply 6x 7 = 42 + 1 = 43

----------

3. Divide 80 by 8

10
8)80             Take the first digit 8 1 times of 8 is 8
8               remainder is zero
---------
00
----------
4. Find the value of k in this given equation 3k + 5 = 23

Solution

3k + 5 = 23

Subtract 5 on both sides

3k + 5-5 = 23-5

3k = 18

Divide by 3 on both sides

p =6

5. Find the value of p in the given equation 4+5p = 2p + 37

Solution

4+5p = 2p + 37

Subtract 4 on both sides

4 - 4 + 5p = 2p + 37 – 4

5p = 2p + 33

Subtract 2p on both sides

5p-2p = 2p – 2p +33

3p = 33

Divide by 3 on both sides

p = 11

6. Find the value of s in the given equation 4s + s -7 = -3s +73

Solution

4s + s -7 = -3s +73

Add 4s + s

5s – 7 = - 3s + 73

Add 3s +7 on both sides

5s+3s-7+7 = 3s-3s+73+7

8s = 80

Divide by 8 on both sides

s = 10

I have recently faced lot of problem while learning Constructing Parallel Lines, But thank to online resources of math which helped me to learn myself easily on net.

Math Home Work Help


Find the value of s in this given equation 7s - 5 = 23
Find the value of m in the given equation 5m = m + 36
Subtract 913 – 2464
Multiply 451 x 18
Divide 256 / 16

Answers


1. s =4

2.m=9

3.667

4.8118

5.16

Tuesday, February 12, 2013

Definition of Expected Value

Definition of expected value:
Expected value learning is one of the most essential concepts in probability. The expected value of a real-respected random variable gives the center of the distribution of the variable, in a special sense.

The expected value may be naturally understood by the law of large numbers: The expected value, when it exists, is almost for sure the limit of the sample mean as sample size grows to infinity.

The term "expected value" can be misleading. It must not be a confused with the "most probable value." The expected value is in a general not typical value that the random variable can take on. It is an often helpful to the interpret the expected value of a random variable as the long-run average value of the variable over many independent repetitions of an experiment. Is this topic Expected Value of Uniform Distribution hard for you? Watch out for my coming posts.


Definition of expected value:

The Definition Expected value (EV):

The expected value is the best prediction of an variable's value, and is the computed by multiplying each outcome by the probability of its occurrence and then averaging them.

The calculated value of a variable quantity which is most likely to occur. If a variable x can take any of the values (x1,x2,…..,xn) with corresponding probabilities (p1,p2,.......,pn) then expected value x or expectation of x is written as E(x)=p1x1+p2x2+…….+pnxn.

The general format of the Expected value is

definition,the Expected Value = Number of problem x Particular probability.

Formula for  expection for function f(x):

E[ f(X) ] = S f(x)P(X = x)

I have recently faced lot of problem while learning Definition of a Rational Number, But thank to online resources of math which helped me to learn myself easily on net.


Definition of Expected value : properties and example problems:


Properties of expected value:

The following properties are used to find the expected value. These properties are shows to the real respected random variable that gives the expected value.from definition

1. Show that E(X + Y) = E(X) + E(Y)

2. Show that E (cX) = cE(X)

3. Show that if X 0 then E(X) 0.

4. Show that if X Y then E(X) E(Y

5. Show that |E(X)| E (|X|)

The above five properties are mainly used in solving a problem of expected value.

Expected values Example:

The Experiment is to rotate a standard roulette wheel, and put money on the table minimum, ten dollars, on red.  Let X is my profit in dollars. X has two possible outcomes:  +20 and –20.  Since there are 18 red numbers out of 68 numbers on the wheel, we have P(X = +20) = 18/68, and P(X = –20) = 40/68.

Sol:

So we have, expection formula for function f(x)

E[ f(X) ] = S f(x)P(X = x)

E(X) = (20) (18/68) + (-20) (40/68) = 5.294-11.764 = - 6.47

On average, I lose a bit over fifty cents every time I place the minimum bet on red.