Showing posts with label math word method. Show all posts
Showing posts with label math word method. Show all posts

Thursday, March 7, 2013

Math Word Method

Introduction of math word:

In mathematics, especially in the area of abstract algebra known as combinatorial group theory, the word problem for a recursively presented group G is the algorithmic problem of deciding whether two words represent the same element. Although it is common to speak of the word problem for the group G strictly speaking it is a presentation of the group that does or does not have solvable word problem.(Source: Wikipedia)

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Math word problems methods:


Math word problems method 1

Twelve years ago, Morgan’s mother was four times older than her daughter. After 12years, the Morgan mother will be twice older than daughter. The present age of Morgan is:

Sol: Let Morgan’s age 12 years ago be x years.

Morgan mother’s age 12 years ago = 4x

(4x+12)+12=2(x+12+12)

x=12

Present age of Morgan= (x+12) = 24years

Answer.24 years

Math word problems method 2

On the first exam of the semester, kisans scored a 75. On the last exam of the semester, kisan scored 95% By what percent did kisan's score improve?

Solution

In first test kisan got 75

In last test he got 95.

% increase in test `( 75(x+100))/100` =95

0.75X+75=95

0.75x=95-75

0.75x=20

x=`20/0.75`

=27%

Answer:= 27%

Math word problems method 3

Orton and Victoria agree to meet in Chicago for the weekend. Orton travels 114 miles and Victoria travels 96 miles. If Orton s rate of   speed is 6mph faster than Victoria ’s then at what rate of speed does Orton travel?

Solution

Take Victoria’s speed =x,

Distance = 96 miles

Then Orton’s speed = x+6,

Distance =114 miles

Distance/speed = time, here time is constant.

Now

`114/(x+6) ` =` (96/x)`

Cross multiply on both sides

114(x)=96(x+6)

114x=96x+576

Subtract 96x on both sides

114x-96x=96x-96x+576

18x=576

Divide by 18 on both sides

`(18/18)x` =`576/18`

We get

x=32 mph

Victoria’s speed=32 mph

For Orton speed= 32+6 =38 mph

Math word problems method 4

The diameter of the driving wheel of a car is 190 cm. How many revolutions per min must the wheel make in order to keep a speed of 75 kmph?

Solution

Distance to be covered in 1 min = `(75*1000)/60` m

=1250m

Circumference of the wheel =2 `pi` r

Radius of the driving wheel = diameter of the driving wheel `/2`

=`190/2`

=95

(2 * `22/7` * 0.95)m=5.966m.

So, Number of revolutions per min   =  `1250/5.966`

=210.

Answer = 210 rpm

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Practice problem for math word method


Find the cost per pound of a coffee mixture made from 7 lb of coffee that costs $8.20 per pound and 11 lb of coffee that costs $6.50 per pound

Answer ;$7.16